5/x^2-4+2/x=2/x-2

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Solution for 5/x^2-4+2/x=2/x-2 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x+5/(x^2)-4 = 2/x-2 // - 2/x-2

2/x-(2/x)+5/(x^2)-4+2 = 0

2/x-2*x^-1+5/(x^2)-4+2 = 0

5*x^-2 = 2 // : 5

x^-2 = 2/5

-2 < 0

1/(x^2) = 2/5 // * x^2

1 = 2/5*x^2 // : 2/5

5/2 = x^2

x^2 = 5/2 // ^ 1/2

abs(x) = (5/2)^(1/2)

x = (5/2)^(1/2) or x = -(5/2)^(1/2)

x in { (5/2)^(1/2), -(5/2)^(1/2) }

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